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0.01x^2-x-200=0
We add all the numbers together, and all the variables
0.01x^2-1x-200=0
a = 0.01; b = -1; c = -200;
Δ = b2-4ac
Δ = -12-4·0.01·(-200)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*0.01}=\frac{-2}{0.02} =-100 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*0.01}=\frac{4}{0.02} =200 $
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